# Inequalities MCQ

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Inequalities MCQ

1. Inequalities are statements which shows an ___________ relationship between any two or more given quantities.

(a)    direct

(b)    unequal

(c)    vertical

(d)    indirect.

Inequalities are statements which shows an  inequal relationship between any two or more given quantities. So, (b) is the correct option.

Inequalities are statements which shows an  inequal relationship between any two or more given quantities. So, (b) is the correct option.

2. An inequation of the from $\displaystyle \mathbf{ax}\text{ }+\mathbf{b}\ge \mathbf{0}$ is known as inequation in one  _________________                  .

(a)    Constant

(b)    Real number

(c)    Variable

(d)    Dependent.

In the inequation $\displaystyle \mathbf{ax}\text{ }+\mathbf{b}\ge \mathbf{0}$, b & a are constant number,  x is the only variable. So, (c) is the correct option.

3. If x > y and z > 0 then

(a)      x – z > y – z

(b) $\displaystyle \frac{x}{y}<\frac{y}{x}$

(c)      xz < yz

(d)     none of the above

x > y and z > 0, So, z is a positive number. So, (x – z) > (y – z). So, (a) is the correct option.

4. If a >0 and b <0, it follows that:

(a) $\displaystyle ~\frac{1}{a}>\frac{1}{b}$

(b) $\displaystyle \frac{1}{a}<\frac{1}{b}$

(c) $\displaystyle ~\frac{1}{a}=\frac{1}{b}$

(d) a = b

a>0 means a is a positive number, b<0 means b is negative number. So, $\displaystyle \frac{1}{a}>\frac{1}{b}$. So, (a) is the correct option.

5. The  linear relationship between two variables in an inequality:

(a) $\displaystyle {ax+\text{ }by\le c}$

(b) $\displaystyle {ax\text{ }by\le c}$

(c) $\displaystyle {ax+\text{ }by+\text{ }c\le 1}$

(d) $\displaystyle {ax+\text{ }by+\text{ }c\le 0}$

The linear relationship between two variables x & y, in an inequality is ax + by <= c. So, (a) is the correct option.

6. Solution of 3(x – 2) > 4x – 3 is

(a)    x > 6

(b)    x < -3

(c)    x < 3

(d)    x > 3

3(x – 2) > 4x – 3, Or,  3x – 6 > 4x – 3, Or,  – 6 + 3 > 4x – 3x, Or,  – 3 > x, Or,  x < – 3. So, (b) is the correct option.

7. If x+ $\displaystyle \frac{1}{4}>\frac{7}{4}$, then

(a) $\displaystyle x>-\frac{3}{2}$

(b) $\displaystyle x>\frac{3}{2}$

(c) $\displaystyle x<\frac{3}{2}$

(d) None of these $\displaystyle x+~\frac{1}{4}>\frac{7}{4},\text{ }so,\text{ }x>~\frac{7}{4}~-\frac{1}{4}.\text{ }Or\text{ }x>\frac{6}{4},\text{ }or\text{ }x>\frac{3}{2}.$
So, (b) is the correct option.